2

Has there been any investigation into the ATR quality of the central alveolar approximant [ɹ]? It is very vowel-like and I have this theory that it could simply be the result of an advanced tongue root and a retracted tongue tip. Is that a crazy idea? I know there is probably more to it than that.

4
  • Are you asking about the /r/ phoneme in English? Or [ɹ] universally? There's a reason why it's called an "approximant".
    – jlawler
    Commented Aug 16, 2013 at 23:35
  • All of the above.
    – Moss
    Commented Aug 17, 2013 at 1:26
  • As far as English /r/ goes, there are quite a few different articulations in use that all pass as acceptable--ATR may well play a role in some. Have a look at this SE-Linguistics question and some of the links therein. Commented Aug 17, 2013 at 7:55
  • Hmm. Yes, that link lead me to some other stuff and I see that there may indeed be multiple articulations for [ɹ]. If only the IPA told the whole story. Now that I try I seem to be able to produce two different styles of r. One that seems to be -ATR (or maybe its pharyngealization, can't tell the difference), the other +ATR. In their extremes the -ATR sounds like a sterotypical Southern States accent and the +ATR sounds like a strong Eastern Canadian. Does that make any sense? I guess [ɹ] is a much more mysterious sound than I was hoping for.
    – Moss
    Commented Aug 17, 2013 at 19:00

1 Answer 1

4

If you are talking about [ATR] the phonological feature, then you will want to know whether there is [-ATR] approximant that alternates with [r] in some language. If you are talking about the physical parameter normally correlated with [ATR] in languages which have that feature, then it gets tricky since the exact articulatory/acoustic correlates to be associated with [ATR] are not fully agreed upon.

For the latter question, see, inter alia, Edmondson and Esling (2009) "The valves of the throat..."; Fulop, Kari and Ladefoged (1998) "An acoustic study of the tongue root contrast..."; and references therein.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.