Semantic types meaning for example a verb being of type (e,t), or an individual/entity being of type e.

I am confused in these two sentences, because I believe the semantic type of 'and' is different in each sentence.

(1) John and Mary run (2) Mary runs and jumps

For (1) I have it being of type (et, (et et)) For (2) I think it is of type (e(e(et,t)))

Because of this I am struggling to provide denotations for them.

  • For (1) I mean <et>, <et>, <et> – Lyhbm Apr 7 '19 at 15:53
  • For (1) I have the VP 'and' as having the denotation: λP[λQ[λx[P(x) ∧ Q(x)]]] – Lyhbm Apr 7 '19 at 15:54
  • Still unsure about number 2 so any help in terms of denotation and derivations would be helpful. – Lyhbm Apr 7 '19 at 15:55
  • This is one of the places the "semantic type theory" breaks down. Conjunctives like and can join any two things, as long as their types are the same: consider "Mary drops and kicks the ball", where it's joining (e(et))s, and so on. – Draconis Apr 7 '19 at 17:02
  • 2
    @Reviewers What do you find unclear about this question? For readers who are familiar with the theory of semantic types, the question is perfectly clear and legitimate. Just because not everyone might know what a type like (e,t) is doesn't mean it's a bad question. Not every question can be worded such that any potential reader knows precisely what is being asked about, some are specific to a particular theory and that's okay as long as it's about linguistics, which this question clearly is. I see no point where this question could of should be improved. – lemontree Apr 8 '19 at 9:19

I will first present a simple solution where "and" conjoins the respective NPs/VPs in such a way that the resulting conjoined elements combine with the VP/subject NP in such as if there was just a single element of the same type as the non-conjoined version. Of course, this is a bit naive for reasons discussed below.

The semantic type of "and" is indeed ambiguous between contexts: Since "and" can be used to conjoin NPs, VPs, sentences or pretty much anything else, it will have a different type in each context.

To find out the type of an expression, I would always do "backwards engineering": See which type you need to get out - this will be the second component of the type - then check what types go in for the arguments - this will be the first comonent of your type - and then simply set (input,output).

For "John and Mary run": "run" is a one-place verb, it referes to a set of individuals and is therefore of type (e,t), so you need to make sure that "John and Mary" are of type "e" because that's the input to "run". So the second component/the output value of the type of "and" will be (...,e). Now "John" and Mary" are proper names, so they refer to individual elements and thus have the type e. These arguments/inputs are absored by "and" one after the other, so the first component must be (e,(e, ...)). Combined, you have that the full type of "and" for the first sentence is (e,(e,(e))). You put in an e "John", then another one ("Mary"), and you get out something of type "e" again ("John and Mary").

 John       and       Mary    run
| e  |  |(e,(e,e))|  | e  | |(e,t)|
|       (e,e)     |  | e  | |(e,t)|
|             e           | |(e,t)|
|                t                |

For "Mary runs and jumps": "runs and jumps" behaves like a one-place verb that takes an NP of type e and returns a truth value, so the output of "and" should be (...,(e,t)). The input arguments are one-place verbs themselves, so to (e,t)'s go in for the arguments. Thus, the type of "and" in the second sentenece is ((e,t),((e,t),(e,t))): You put in an (e,t) ("runs"), then another one ("jumps"), and end up with a new something of type (e,t) ("jumps and runs").

 Mary     runs            and              jumps
| e  |  |(e,t)|  |((e,t),((e,t),(e,t)))|  |(e,t)|
| e  |  |            ((e,t),(e,t))     |  |(e,t)|
| e  |  |                 (e,t)                 |
|                        t                      |

Obviously, the two different types have something in common: In both useage contexts, you have two inputs of the same type and an output of yet the same type. For NPs, the type works with e, for one-place verbs, the type goes with (e,t), and with propositions (for example "John runs and Mary jumps") you would have the same with type t. So you could generalize and say that "and" is of type (σ,(σ,σ)) for any type sigma. In polymorphic type theory, this can be expressed as ∀σ.(σ,(σ,σ)).
I have to disagree with Draconis' comment in this respect: It's not like the entire theory of semantic types breaks down over "and", it's just that simply typed expressions are not quite powerful enough to generalize over such observations. But there are of course type theories that can accuont for these kinds of phenomena. Another extension that allows to provide types where simply types fail is intersection types, where one expression can basically have two types simultaneously and you can pick out one of the types depending on which you need in a particular context.

Going back to my introductory remark, this analysis is of course a bit naive: You assume that "John and Mary" is of the same type as just "John", namely of type e. This is philosophically a bit questionable, because e is supposed to denote indivdiual entities, and "John and Mary" arguably are not one individual. This is maybe less severe for the conjunction of NPs, where the predication of singing and dancing indeed behaves like a one-place verb that denotes a set of individuals, but still one could argue that this is not the desired structure.
Under some analyses, but in particular if one were to formalize the two sentences in predicate logic, one would traditionally claim that in both of the sentence we have a so-called ellipsis: "John and Mary run" is actually "John runs and Mary runs", just with the first "run" not visible, and "Mary runs and jumps" is actually just a contraction of "Mary runs and Mary jumps". Under this analysis, "and" can only conjoin propositions, and is thus of type (t,(t,t)), the remaining sentence then needs to be re-analyzed accordingly. This is precisely what you already assumed: λP[λQ[λx[P(x) ∧ Q(x)]]] would be the proper formalization of (2), and (1) would be λP[λx[λy[P(x) ∧ Q(y)]]]. In both cases, ^ is of type (t,(t,t)). The respective types of the composed expresions would be

   λP [   λQ  [ λx[P(x) ∧ Q(x)]]] 
((e,t), ((e,t), (e,     t     )))

   λP [ λx[ λy[P(x) ∧ Q(y)]]]
((e,t), (e, (e,    t      )))
  • "This is philosophically a bit questionable, because e is supposed to denote indivdiual entities, and "John and Mary" arguably are not one individual" It's not problematic, if Mary may be a face and a voice and a character ..., and perhaps more than a sum of parts. (e) is similar to a preposition, a type to be proved distinct from void (or the empty set, null, nil, bottom, false--I'm not firm in type theory). That doesn't change much with a recursive type. But it's elementary on the language level, if we inflect for count, and rather problematic with or in it or they has/have .... – vectory Apr 7 '19 at 20:19
  • Back in my day, names were of type (et, t), i.e. they denoted sets of properties. – David Vogt Apr 8 '19 at 11:06
  • @DavidVogt Sure, that's possible and philosophically not unreasonable. However, one then needs to make sure that this type fits with the (e) in (e,t), so you'd either need some implicit type conversion or re-fit the type of the verb accordingly. Following OP's own suggestions, I tried to keep it simple, and the assumption that the denotation of a proper name is an individual which in turn are of type e is not uncommon. – lemontree Apr 8 '19 at 16:41
  • Thanks for the helpful answer. But I agree with some of the comments that this is questionable. It's going to need major augmentation when confronted with nonconstituent conjuncts, e.g. Frank saw [Mary today] and [Jim yesterday] Beyond coordination, there is no evidence that strings like Mary today are constituents. And if one nevertheless views them as constituents, what type would they be? Note also that in such cases, there is evidence that ellipsis is NOT involved. – Tim Osborne May 2 '20 at 1:36

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