Using the formal syllable identification rules, you have the following (with an example pronunciation):
MacDonald => Mac + Don + ald (`/məkdˈɒnl̩d/`)
McDonald => McDon + ald (`/məkdˈɒnl̩d/`)
Kvitova => Kvit + o + va (`/kəvˈɪtəvə/`)
Here, the number of vowel sounds (syllabic or not) in the last two examples does not match the syllable split. A (/ə/
) has been inserted between two of the consonants.
Does this pronunciation pattern change the syllabification rules to align with the number of spoken vowel/syllabic consonant sounds, or is it more a pattern of speech to smooth over adjacent consonants that do not flow easily together (e.g. the kv
pair in kvitova
)?
With Mc
, should this be considered a prefix like be
, de
and others are, and be considered a syllable on its own -- that is, should it follow the syllable pattern of MacDonald
?
If Mc
should be considered a syllable, is the c
the nucleus? If so, does that make the /k/
phoneme syllabic?
Mc
has the/@/
vowel, so should be considered a syllable. However, there is no vowel to be the nucleus. Therefore, the letterc
should form the nucleus and@k
should be syllabic. That is, you don't pronounceMcDonald
as/mkʼdˈɒnl̩d/
or similar (i.e. an ejective or implosive/k/
)./@/
as you have written, I'm assuming schwa. Letters don't form nuclei, sounds do. You have a string of two letters representing a string of three sounds. You pronounceMcDonald
as/m@kdon@ld/
or/m@kdonld/
, etc.McDon
is a syllable. He says thatMc
is a syllable whose nuclear vowel /ə/ is not represented in the spelling. He denies your claim that it has no nuclear vowel.